Find the center of the circle whose equation is (x-2)^2(y-4)^2=9.
A.(-2,-4)
B.(2,4)
C.(4,2)

B.(2,4)

Step-by-step explanation:

The equation for a circle is written as

(x-h)^2 +(y-k)^2 = r^2

where (h,k) is the center and r is the radius

(x-2)^2+(y-4)^2=9.

Rewriting this equation

(x-2)^2+(y-4)^2=3^2

The center is at (2,4)

the reporter's right

step-by-step explanation:

1/4 = .25 / 25%

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°