Charmaine , dale , and Justin have a total of 116$ in their wallets. Dale has 8$ more than charmaine. Justin has 4 times what charmaine has . How much does each have ?

The amount Charmaine has $18, Dale has $26 and Justin has $72.

Step-by-step explanation:

Given:

Charmaine , dale , and Justin have a total of 116$ in their wallets. Dale has 8$ more than charmaine. Justin has 4 times what charmaine has.

Now, to find each have.

Let the amount of Charmaine be

So, the amount of Dale has =

And, the amount of Justin has =

The total amount of Charmaine , dale and Justin have = $116.

Now, to get the amount of each we put an equation:

Subtracting both sides by 8 we get:

Dividing both sides by 6 we get:

The amount Charmaine has = $18.

Now, substituting the value of :

The amount Dale has = $26.

The amount Justin has = $72.

Therefore, the amount Charmaine has $18, Dale has $26 and Justin has $72.

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.

i dont know men

step-by-step explanation: