A 24.6 g marble sliding to the right at 62.0 cm/s overtakes and collides elastically with a 12.3 g marble moving in the same direction at 15.5 cm/s. After the collision, the 12.3 g marble moves to the right at 77.5 cm/s. Find the velocity of the 24.6 g marble after the collision. cm/s

Velocity of the 24.6 g marble is 31 cm/s.

Step-by-step explanation:

Given:

Marble 1:

Mass of the marble = 12.3 gm

Velocity of before collision = 15.5 cm/s

Velocity of after collision = 77.5 cm/s

Marble 2:

Mass of the marble = 24.6 gm

Velocity of before collision = 62 cm/s

Velocity of after collision = ?

From the law of conservation of momentum, we know that momentum before equals the momentum after :

So,

⇒

⇒

⇒ Plugging the values.

⇒

⇒

⇒

⇒ ...subtracting both sides 953.25

⇒

⇒ ...dividing both sides with 24.6

⇒

⇒ cm/s

The velocity of the 24.6 g marble after the collision is 31 cm/s and it will move opposite to of the 12.3 g marbles that is towards left.

23

step-by-step explanation:

arrange the equations with like terms in columns.

analyze the coefficients of x or y.

add the equations and solve for the remaining variable.

substitute the value into either equation and solve.

check the solution.

step-by-step explanation: