A triangle has side lengths of 11 inches, 15 inches, and 20 inches. Find the angle measures of the triangle. Round decimal answers to the nearest tenth.

I don't know but I have the equations. (also Im going to assume you know a bit of trig)

Step-by-step explanation:

You have to use law of cosines.

a=11

b=15

take these equations and plug in the variables

a^2=b^2+c^2-2bc cos(a)

b^2=a^2+c^2-2ac cos (b)

c^2=a^2+b^2-2ab cos(c)

you will get something along the lines of

something=cos a

something=cos b

something=cos c

then in a calculator you push inverse cos or cos-1(x) and input the "something" into as x and that answer should be one angle, and repeat it for the rest of the three values.

(3x-8) or (3x+8)

step-by-step explanation:

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.