Let

yequals=left bracket Start 3 By 1 Matrix 1st Row 1st Column 3 2nd Row 1st Column negative 8 3rd Row 1st Column 3 EndMatrix right bracket

3

−8

3

,

Bold u 1u1equals=left bracket Start 3 By 1 Matrix 1st Row 1st Column negative 2 2nd Row 1st Column negative 4 3rd Row 1st Column 1 EndMatrix right bracket

−2

−4

1

,

Bold u 2u2equals=left bracket Start 3 By 1 Matrix 1st Row 1st Column negative 4 2nd Row 1st Column 1 3rd Row 1st Column negative 4 EndMatrix right bracket

−4

1

−4

.

Find the distance from y to the plane in

set of real numbers R cubedℝ3

spanned by

Bold u 1u1

and

Bold u 2u2.

3.3

Step-by-step explanation:

We determine the plane formed by and . The normal to the plane is given by their cross product:

The equation of the plane is then given by

The distance between a vector and a plane is given by

Comparing,

Substituting,

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)

answer: give more info

step-by-step explanation: