Look at the figure below:

an image of a right triangle is shown with an angle labeled y

If sin y° = 7 over q and tan y° = 7 over r, what is the value of sec y°?

sec y° = q over r
sec y° = 7r
sec y° = 7q
sec y° = r over q

sec y° = q over r ⇒ 1st answer

Step-by-step explanation:

Let us revise some trigonometry ratios

∵ sin y° =

∵ tan y° =

- Substitute tan(y) by

∴    =

- To find sec y° divide by sin(y)

∵ ÷ sin(y) = ÷

- Change (÷) to (×) and reciprocal the term after (÷)

× = ×

- Simplify the left hand side by divide up and down by sin(y)

   and the right hand side by divide up and down by 7

∴ =  

∵  sec y° =  

∴ sec y° =  

∴ sec y° = q over r

the answer is here: : )

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idk

step-by-step explanation: