A satellite's escape velocity is 6.5 mi/sec, the radius of the earth is 3960 mi, and the earth's gravitational constant is 32.2 ft/sec^2. How far is the satellite from the surface of the earth

ft

Step-by-step explanation:

This is the formula to find satellite's escape velocity V , where R is earth's radius, h is the satellite's height from the earth surface and g is the earth's gravitational constant.

  (Multiplying to clear the fractions)

(R+h)

Now, we can determine height of satellite from the surface of the earth

by putting the values in above equation

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step-by-step explanation:

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step-by-step explanation:

told you