Yori is trying to prove that if segment AB is a perpendicular bisector of segment PQ, then any point, X, on segment AB is equidistant from endpoints P and Q. What is the best plan for her proof?

The angles between the vertices y'P0 and y'Q0 must be equal

α=β

Step-by-step explanation:

To demonstrate that each point of segment AB is equidistant from the end points P and Q, it is enough to take any point of segment AB and determine the angle formed between this point and points P and Q

According to the graph the angles generated by the vertices y'P0 and y'Q0 must be equal, and these are determined by the sine, cosine or tangent, we will take for example the tangent

tgα=y'/P = 5/-6 ⇒ α=atg(5/-6) ≅ -39,80° ∧ tgβ=(5/6) ⇒ β=atg(5/6) ≅ 39,80°

The negative sign indicates that the tangent is negative in that quadrant (2nd) , finally α=β

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet