Find 3 consecutive odd numbers where the product of the smaller two numbers is 22 less than the square of the largest number.

1,3,5

Step-by-step explanation:

1) your 3 consecutive odd integers would be x,x+2,x+4

The smaller two integers are:x and x+2

So

(X)(x+2)=(x+4)^2-22

Distribute

X^2+2x=x^2+16+8x-22

X^2 cancels each other out and 16-22=-6

2x=8x-6

Add 6 on both sides

2x+6=8x

Subtract “2x” on both sides

6=6x

1=x

Hope this helps!

  answer:

  write 548 as 500 + 40 + 8. multiply each addend by 5. then add the three products to get 2,740.

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