What is the area of a triangle whose sides have length $\sqrt{70},$ $\sqrt{70},$ and $\sqrt{28}$?

it’s supposed to be -4+45=41

step-by-step explanation:

130.66 for edgedunity students

yx = 36

step-by-step explanation:

cos f = opposite side/ hypotenuse

cos f = yw / yx

we know cos f = 4/9 and yw =16

4/9 = 16/yx

multiply each side by yx

4/9 yx = 16/ yx * yx

4/9 yx = 16

multiply each side by 9/4

9/4 * 4/9 yx = 16 *9/4

yx = 36