A hexagonal pyramid that has a slant height of 39 cm and its hexagonal base has a radius of 10√3 cm.
What is the volume of the pyramid?

225

Step-by-step explanation:

Volume of the pyramid is calculated as 1/3 bh, where b is base and h is height

Given height as 39cm and a base of 10√3cm = 10 x √3, where √3= 1.73; base = 10 x 1.73 = 17.3

Slot the values into the formula:

Volume = 1/3 × 17.3 x 39

= 1/3 × 674.7 = 674.7/3

Volume = 224.9 approximately 225.

I hope this helps.

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