Let p1 be the proportion of successes in the first population and let p2 be the proportion of successes in the second population. Suppose that you are testing the hypotheses: H0:p1−p2=0Ha:p1−p2≠0 Futhermore suppose that z∗=1.73, find and input the p-value for this test. Round your answer to 4 decimal places.

0.0836

Step-by-step explanation:

Given that p1 be the proportion of successes in the first population and let p2 be the proportion of successes in the second population

is the hypotheses created

This is two tailed

Test statistic Z = 1.73

corresponding p value

= 0.08363

=0.0836 (after rounding off to 4 decimals)

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.