D= {x|x is a whole number} e = {x|x is a perfect square between 1 and 9} f = {x|x is an even number greater than or equal to 2 and less than 9} which of the following is d ∩ f? a. {4, 6} b. {2, 4, 6} c. {2, 4, 6, 8} d. {2}

Correct option is:

c. {2, 4, 6, 8}

Step-by-step explanation:

d = {x|x is a whole number}

i.e. d={0,1,2,3,...}

f = {x|x is an even number greater than or equal to 2 and less than 9}

i.e. f={2,4,6,8}

Intersection(∩) of two sets gives the element which is common in both the sets

d∩f={0,1,2,3,...}∩{2,4,6,8}

     = {2,4,6,8}

Hence, Correct option is:

c. {2, 4, 6, 8}

step-by-step explanation:

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11