Say you go kayaking over a 2 mile stretch of river. The river is flowing at a speed of 1mph. You go 2 miles upstream, and then 2 miles downstream, back to your starting point, for one round trip. Make a function for it, then give me the graph of this function. Use a share link from Desmos, or upload a picture, or scan the graph you made on a piece of paper. Remember to show all vertical asymptotes and any horizontal asymptote.

4 mph

Step-by-step explanation:

Givens

Current = c = 2 mph

Alberta = r = ?

d = 2 mph upstream

d1 = 6 mph downstream

Formula

d = r * t

The time is the same so the formula becomes d/r = t

2/(r  - 2) = 6/(r + 2)    

Solution

Cross Multiply

2*(r + 2) = 6*(r - 2)

2r + 4 = 6r - 12                      Subtract 2r from both sides

4 = 6r - 2r - 12                       Combine the right.

4 = 4r - 12                             Add 12 to both sides.

4 + 12 = 4r

16 = 4r                                  Divide by 4

16/4 = 4r/4

r = 4

536

step-by-step explanation:

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).