A car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 11 ft/sec2. How long before the car stops? Round your answer to one decimal place.

The distance the have traveled before come into the rest = 72.72 ft

Step-by-step explanation:

Velocity of the car u = 40

Final velocity of the car V = 0

Acceleration of the car a = - 11

First equation of motion,

V = u - at --------- (1)

Put all the values in equation 1, we get

0 = 40 - 11 t

⇒  t = = 3.636

Now the distance traveled by the car before come into rest  

Put all the values in the above equation we get,

S = 40 × 3.636  - × 11 ×

S = 145.44 - 72.71

S = 72.72 ft

This is the distance the have traveled before come into the rest.

it has changed from the width and the height.

step-by-step explanation: