A 90 k g shopper is standing on an escalator that makes a 25 ∘ incline with the horizontal. The escalator carries the shopper to the next floor, a height 30 m above ground level, at a constant speed. Calculate the work that the escalator does on the shopper.

W= 27 k J

Step-by-step explanation:

Given that

mass ,m = 90 kg

Height , h= 30 m

angle , θ = 25°

The work done by escalator is given as follows

W  = m g h

Work done by escalator does not depends on the angle ,it depends only on  height.

Now by by putting the values in the above equation we get

W= 90 x 10 x 30 J            ( take g = 10 m/s² )

W= 27000 J

W= 27 k J

Therefore work done by escalator will be 27 k J.

answer: on kudzu, being female and being green are independent events.

step-by-step explanation:

answer: 7 x 2/5 = 2.8 hours, is your answer. your welcome! : 3

step-by-step explanation: first work out how long it took to hose 1/7 of the lawn which is 2/5 hours. times that by 7 to get the whole lawn.

sorry i don't know the other answer. i didn't learn what a proportional relationship is.