Suppose we have an urn containing 9 marbles. Two are red, three are green, and four are blue. We randomly select 5 marbles from the urn, with replacement. What is the probability of selecting 3 green marbles, 1 red marble, and 1 blue marbles?

probability of selecting 3 green marbles, 1 red marble, and 1 blue marbles

Step-by-step explanation:

Given data urn containing '9' marbles

given  red marbles = 2

         green marbles =3

          blue marbles = 4

Five marbles can be selected at a time from '9' marbles in   ways

by using  formula

After simplification , we get

         total number of ways n(S) = 126

The probability of selecting '3' green marbles ,one red marble and one blue marble with replacement.

let ' E' be the event of selecting '3' green marbles ,one red marble and one blue marble with replacement.

n(E) =  ways

The required probability

on simplification , we get

answer: the answer is 127 degrees

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5