Mr. Nguyen bought a package of 4 chicken legs and a package of 6 chicken wings. Ms. Dawen bought a package of 3 chicken legs and a package of 6 chicken wings. Mr. Nguyen bought 52 ounces of chicken. Ms. Dawen bought 45 ounces of chicken. How much did each chicken leg and each chicken wing weigh? Let x represent the weight of the chicken leg and y represent the weight of the chicken wing.

Chicken leg (x) = 7 ounce

Chicken wing (y) = 4 ounce

Step-by-step explanation:

Let x represent the weight of Chicken leg

Let y represent the weight of Chicken wing

Mr. Nguyen bought 4 chicken legs and 6 chicken wings which collectively weighed 52 ounces i.e. 4x + 6y = 52

Ms. Dawen bought 3 chicken legs and 6 chicken wings that collectively weighed 45 ounces i.e. 3x + 6y = 45

We have two equations, to get the weight of each variable x and y, we use the elimination method of simultaneous equation to solve.

Eqn 1 4x + 6y = 52

Eqn 2 3x + 6y = 45

We subtract each variable in eqn (2) from that of eqn (1). i.e.

4x - 3x, 6y - 6y and 52 - 45

We then have; x + 0 = 7

Thus, x = 7

To get y, we substitute x in eqn 2

Since 3x + 6y = 45

3(7) + 6y = 45

21 + 6y = 45

6y = 45 - 21

6y = 24

y = 4

Thus x=7 and y=4. This means that the weight of the chicken leg is 7 ounces and that of the chicken wing is 4 ounces.

27 + 13x + 15 = (x + 5)( =

step-by-step explanation:

27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( =