A spherical balloon is inflating with helium at a rate of 64 pi StartFraction ft cubed Over min EndFraction . How fast is the balloon's radius increasing at the instant the radius is 2 ft?

The radius of the balloon is increasing at a rate of 4 feet per minute.

Step-by-step explanation:

We are given the following in the question:

Volume of sphere is given by

where r is the radius of the balloon.

Instant radius, r = 2 ft

Rate of change of volume =

Putting values, we get,

Thus, the radius of the balloon is increasing at a rate of 4 feet per minute.

3-4

step-by-step explanation:

the answer is 3-4 because both 45 and 60 has a multiple of 15.

45/3=15

60/4=15

therefore the odds against selecting a red is 4-3

a) 7x=7

step-by-step explanation: