What is the equation of the line perpendicular to -2x+3y=9 through (-1,-3) in standard form?

Explanation:

Anything perpendicular to Ax+By = C is of the form Bx-Ay = D

Note the swap of A and B, and how the plus sign changed to a minus sign.

In the case of -2x+3y = 9, we see that A = -2, B = 3, and C = 9.

So Bx-Ay = D updates to 3x-(-2)y = D which simplifies to 3x+2y = D

To find the value of D, plug in the given point (x,y) = (-1,-3) and simplify

3x+2y = D

D = 3x+2y

D = 3(-1) + 2(-3) ... plug in x = -1, plug in y = -3

D = -3 - 6

D = -9

Now we can say  3x+2y = D turns into  3x+2y = -9

Therefore, the line that is perpendicular to -2x+3y = 9 and it goes through (-1,-3) is 3x+2y = -9

2 and 1.

step-by-step explanation:

plug in each answer. 0 doesn't work, 1 does. so does 2. 4 doesn't:

0 = 1 is not true.

2 = 2 is true.

4 = 4 is true.

8 = 16 is not true.

hope this !

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5