If the endpoints of a diameter of a circle are (6,2) and (0, 2); what is the radius of
the circle?

The radius of circle is 3

Step-by-step explanation:

Given the endpoints of diameter of a circle are (6,2) and (0,2)

We know that the equation of circle is

+ =

where (x,y) is any point on the circle, (h,k) is center of the circle and r is radius of circle.

To find (h,k): the center is midpoint of diameter

Midpoint of diameter with end points (x1,y1) and (x2,y2) is given by

( , )

( , )

(3, 2)

Hence (h,k) is (3,2)

Substituting values of (h.k) and (x.y) as (3,2) and (0,2) respectively, we get

+ =

=

r =3

Hence the radius of the circle is 3

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb