Suppose that y varies directly as x . if y is 24 when x is 6, find the constant of variation and the direct variation equation

Step-by-step explanation:

Direct variation can be modeled by y = kx where k is the constant of variation!

So to solve for k all we need to do is substitute in the value for y and x that are given.

So according to the problem y = 24 when x = 6

24 = 6k

Divide both sides by 6

k = 4

So the constant of variation is 4

The direct variation equation would then be

y = 4x

what do you mean by fog

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°