Circle B with center B(0, 2) that passes through (6, 0)

(

( x - 0)^2 + (y - 2)^2 = 40

Step-by-step explanation:

We are asked to find the equation of a circle

Step 1: find the radius

( x - a) ^2 + ( y - b) ^2 = r^2

(a, b) - center of the circle

(x, y) - any point on the circle

r^2 - radius of the circle

Using the center

( a, b) = ( 0 , 2)

(x , y) = (6 , 0)

(a, b) = (0 , 2)

a = 0

b = 2

Inserting the values given into the equation

( x - a)^2 + ( y - b) ^2 = r^2

( x - 0)^2 + (y - 2)^2 = r^2

Step 2: sub (x, y) = ( 6 , 0)

x = 6

y = 0

( 6 - 0)^2 + ( 0 - 2)^2 = r^2

6^2 + (-2)^2 = r^2

36 + 4 = r^2

40 = r^2

Step 3: sub the radius into the equation

(x - 0)^2 + ( y -2)^2 = r^2

( x - 0)^2 + (y - 2)^2 = 40

The equation of the circle is

( x - 0)^2 + ( y - 2)^2 = 40

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°