Please help me. I really need it

We're asked to find the number of solutions to this system of equations:

\begin{aligned} y&=-6x+8 3x+y&=-4 \end{aligned}

y

3x+y

​

=−6x+8

=−4

​

Let's put them in slope-intercept form:

\begin{aligned} y&=-6x+8 y&=-3x-4 \end{aligned}

y

y

​

=−6x+8

=−3x−4

​

Since the slopes are different, the lines must intersect. Here are the graphs

Step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

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step-by-step explanation: