At the end of the day a cashier counted 140 quarters and nickels in the register. The coins total 19 dollars. How many coins of each kind was in the register?

80 nickels and 60 quarters.

Step-by-step explanation:

The cashier counted a total of 140 quarters and nickel.

Let the number of nickels=n

Let the number of quarters=q

That means:

n+q=140. (1)

Now, A nickel=5 cents=$0.05

Similarly, 1 Quarter = 25 cents=$0.25

The coins total $19

Therefore:

0.05n+0.25q=19. (2)

We solve the two equations simultaneously.

n+q=140. (1)

0.05n+0.25q=19. (2)

From (1)

n=140-q

Next we substitute n=140-q into equation (2) to solve for q.

0.05(140-q)+0.25q=19

Opening the brackets

7-0.05q+0.25q=19

Collecting like terms

-0.05q+0.25q=19-7

0.2q=12

q=60

From Equation (1)

n=140-q

n=140-60=80

Therefore, there were 80 nickels and 60 quarters.

cant open file sorry!

step-by-step explanation:

multiplication is multiplication.   it might feel harder depending on what level of math you are in, but generally it will be the same old stuff, while implementing some new concepts and methods of solving work.