A car is moving with an initial velocity of 10 mph accelerates at the rate of a(t)=2.5t mph per second for 5 seconds. How fast is the car going when the 5 seconds are up?

i need the statement

step-by-step explanation:

hello there!

i believe the answer is

(cot2+1)/sec2=cot2

    csc2/sec2=cot2

  (1/sin2)/(1/cos2)=cot2

  (1/sin2)(cos2/1)=cot2

  cos2/sin2=cot2

  (1/tan2)=cot2

  (cot2)=(cot2)

hope this !

hyperz ^_^

they r 125, and 216

so the sequence goes 1,8,27,64,125,216

b: y = 2x + 2

step-by-step explanation:

y = 2x + 1

we want a line that is parallel, so it will have the same slope

the line is in the form y= mx+b, so the slope is 2

we have a slope and the y intercept (0,2)

since x is 0 we know the y point which is the y intercept

we can use y= mx+b to write the equation of the line

m is the slope and b is the y intercept

y = 2x +2