2x-5y=9
3x+4y=2
solve the simultaneous equations

First, we will solve the second equation for . Subtract from both sides of the second equation.

Divide both sides of the second equation by .

Substitute the value of from the second equation into the first.

We will solve the first equation for .

Distribute the to the .

Combine the like terms.

Add on both sides.

Divide both sides by .

Multiply both sides by .

Substitute the value of into the second equation.

Multiply.

Add.

x = 2

y= -1

Step-by-step explanation:

to solve this simultaneous equation, using substitution method, we say

let

2x-5y=9 equation 1

3x+4y=2 equation 2

from equation 2

3x+4y=2 equation 2

3x = 2-4y

divide both sides by 3

3x/3 = ( 2-4y)/3

x = ( 2-4y)/3 equation 3

substitute for x , x = ( 2-4y)/3in equation 3 in equation 1

2x-5y=9 equation 1

2(2-4y)/3 - 5y = 9

4 -8y/3 - 5y = 9

multiply through by 3

3 [(4-8y)/3] - 3(5y) = 3(9)

4 - 8y - 15y = 27

-23y = 27-4

-23y =23

divide both sides by the coefficient of y which is -23

-23y/-23 = 23/-23

y = -1

put y = -1 in equation 3

x = ( 2-4y)/3 equation 3

x = (2 -4(-1)]/3

x = (2 +4)/3

x = 6/3

x = 2

therefore the value of x and y is 2 and -1 respectively

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)