Help plz

In a factory that makes bolts, 20% of the bolts being made by a certain machine are defective. The factory owner wants to determine the probability that two bolts in a row will be defective. He decides to use random numbers as a simulation tool. The following list shows 100 two-digit numbers that were randomly generated to represent two bolts in a row. If he uses the digits 0 and 1 to represent defective bolts, how many times were two bolts in a row defective?

a.0

b.33

c.3

d.18

every 5 customers that walk in, only 2 buy popcorn.

step-by-step explanation:

basically 2/5.

brainliest would be appreciated.

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

60.9774

step-by-step explanation:

because when you add 47.6 plus 7.32 equals 54.92

and when you add .0574 + 6= 6.0574

and when you add 54.92 and 6.0574 you get the answer of 60.9774.

plzz mark brainlest last one got deleted. cause i didn't explain it but i did but i understand what the mod meant

the answer to question 1 is -8, 28.

step-by-step explanation: