Write an equation for the line that is parallel to y = −2x and passes through the point (0, −7).

y = -2x -7

Step-by-step explanation:

Parallel lines have the same slope

y = -2x has a slope of -2

The parallel line will have a slope of -2

It goes through a point of (0,-7).  This would be the y intercept

y = mx+b

y = -2x -7

y=-2x-7

Step-by-step explanation:

y = −2x, then slope=-2.

The lines are parallel so the slope is the same.

(0,-7)x1 =0,y1=-7

y-y1=-2(x-x1)

y-(-7)=-2(x-0)

y+7=-2x

y=-2x-7

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation: