What is the factored form of 2x2 + x-3?
(2x+3)(x-1)
(2x + 1)(x-3)
(2x-3)(x + 1)
(2x - 1)(x + 3)

Step-by-step explanation:

a = 2, b = 1, c = -3

We need to factor this by finding the product of a and c, then from there find which factors of a * c will either add or subtract to give us b.

a * c = 6  and the factors of 6 and 1 and 6, 2 and 3.  Well, 6 - 1 doesn't equal 1 and neither does 6 + 1.  So our factors are 3 and 2.  In order to combine those to get a 1 (our b), we will subtract 2 from 3 since 3 - 2 = 1.  That means that 3 is positive and 2 is negative.  Filling in the formula with 3 and 2 in place of 1 looks like this (always remember to put the absolute value of the largest number first):

Group the first 2 terms together and the second 2 term together in order to factor:

and factor out what's common in each set of parenthesis.

Notice that when we factor out a -1 from the second set of parenthesis, we can distribute it back in to get the equation we started with.  We know that factoring by grouping "works" if what is inside both sets of parenthesis is exactly the same.  Ours are identical: (2x + 3).  That is common now, and can be factored out:

That matches your first choice

over the argument its not good to fight.

step-by-step explanation:

f(x)=2x^2 -1 

translation is a function transformation that transform the function in a way of translating. by translating the function its graph is moved  up an down. moving the function f(x) 2 units to the left will be the new function g(x) with the equation: g(x)=f(x+2)=2(x+2)^2 -1