The power, in watts, dissipated as heat in a resistor varies jointly with the resistance, in ohms, and the square of the current, in amperes. A 15-ohm resistor carrying a current of 1 ampere dissipates 15 watts. How much power is dissipated in a 5-ohm resistor carrying a current of 3 amperes?

The power dissipated is 45W.

Step-by-step explanation:

The power varies jointly with resistance , and the square of current :

,

where is the constant of proportionality.

Now we are told that when and , :

solving for we get

,

which gives

With the value of in hand, we find the power dissipated when and

Thus, the power dissipated is 45W.

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

my guess would be b and d, but i didn’t actually get out the pen and paper. lol