A Norman window is a window with a semi-circle on top of regular rectangular window. What should be the dimensions of the window to allow in as much light as possible, if there are only 12 ft of the frame material available? Please find the height of the norman window

1.68 ft

Step-by-step explanation:

Let x be the radius

Arc length = 3.14x

Width = 2x

Height = [12 - (2x) - 3.14x]/2

= 6 - 2.57x

Area = 3.14x²/2 + 2x(6 - 2.57x)

Area = 12x - 3.57x²

dA/dx = 12 - 7.14x = 0

x = 1.6806722689

Height = 6 - 2.57x

= 1.6806722689

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

i think it would be c

mark brainliest if im right

step-by-step explanation: