Daryl has a total of 160 National Football League (NFL) trading cards from both the American Football Conference (AFC) and the National Football Conference (NFC). The number of AFC cards is 8 more than three times the number of NFC cards. Which system of equations can be used to find how many AFC cards, A, and NFC cards, N, Daryl has?
A.
A = 3N
A - 160 = N

B.
A + N = 160
A = 3N + 8

C.
A + N = 160
N = 3A - 8

D.
A - N = 160
N = 3A + 8

B

Step-by-step explanation:

Since A represents the number of AFC cars and N represents the number of NFC cards, and that Daryl has 160 total cards, then A+N = 160, the total number of cards. Furthermore, the number of AFC cards Daryl has is 8 more than 3 times the number of NFC cards, so A would be equal to 8 + 3N, or A = 3N + 8. The only system of equations with both of these correct equations is B.

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: