Not all visitors to a certain company's website are customers. In fact, the website administrator estimates that about 5% of all visitors to the website are looking for other websites. Assuming that this estimate is correct, find the probability that, in a random sample of 5 visitors to the website, exactly 3 actually are looking for the website.

2.14344%

Step-by-step explanation:

There are two possible outcomes here, the visitor looking for the websites (p=0.95) and the visitor looking for other websites(q=5%= 0.05). The question asking for the probability of exactly 3 visitors actually looking for the website(X=3) out of 5 visitors (n=5).  There is no marking to differentiate the visitors, so the order of the visitors is not important.

The calculation will be:

P(X=x) = nCx ×(p)^x ×(q)^n-x

P(X=3) = 5C3 ×(0.95)^3 ×(0.05)^2

P(X=3) =2.14344%

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this

50x5=$250

step-by-step explanation: