If the endpoints of the diameter of a circle are (−8, 0) and (−12, 2), what is the standard form equation of the circle?

The standard form equation of circle is

+ = 5

Step-by-step explanation:

Given the endpoints of diameter of circle (-8,0) and (-12,2)

The equation of circle is given by

+ =

where (x,y) is any point on circle, (h,k) is center of circle and r is radius of circle

To find (h, k): center of circle is given by the midpoint of diameter

Midpoint of diameter with endpoints (x1,y1) and (x2,y2) is

(   ,  )

Substituting the values of endpoints

(   , )

(-10,1)

(h,k) is (-10,1)

Substituting the values of (h,k) and (x,y) as (-10,1) and (-8,0) respectively in equation of  circle we get,

+ =

= 5

Now substituting the values  of (h,k) and , we get

The standard form equation of circle as

+ = 5

f(x) is going down by 4

step-by-step explanation:

(its either that or its going left by 4)

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.