One person is selected at random from a class of 20 males and 13 females. Find the odds against selecting a male and a female

Odds for male= 1.538

Odds for female =  0.65

Step-by-step explanation:

The question is asking for odds, not a probability. A probability shows how much the chance for the event to happen, so it can be expressed as a percentage. Odds show how the event more likely to happen compared to the chance it did not happen. If an event has a 90% probability, the odds will be 90:10= 9

In this case, the odds of selecting a male will be:  

number of male : number of female= 20:13 = 1.538

The odds of selecting a female will be

number of female : number of male = 13/20 = 0.65

51

step-by-step explanation:

73-22=51 the   mass number minus the amount of protons gives you the amount of neutrons

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft