![10.08+4.99x\leq 50](/tpl/images/0558/1991/ac63b.png)
![x\leq 8](/tpl/images/0558/1991/fa660.png)
The maximum pounds of cheese that Ariana can buy is 8
Step-by-step explanation:
Let
x ---> the amount of cheese In pounds, that Ariana can buy
we know that
The cost of 3 loaves of bread plus the cost of the cheese must be less than or equal to $50
so
The inequality that represent this situation is
![3(3.36)+4.99x\leq 50](/tpl/images/0558/1991/278b4.png)
![10.08+4.99x\leq 50](/tpl/images/0558/1991/ac63b.png)
solve for x
subtract 10.08 both sides
![4.99x\leq 50-10.08](/tpl/images/0558/1991/a219a.png)
![4.99x\leq 39.92](/tpl/images/0558/1991/28c83.png)
divide by 4.99 both sides
![x\leq 8](/tpl/images/0558/1991/fa660.png)
Therefore
The maximum pounds of cheese that Ariana can buy is 8