Find hcf and lcm of 120 and 140 by using fundamental theorem of arithmetic

20 and 4200

Step-by-step explanation:

Express the numbers as products of their prime factors.

120 = 2 × 2 × 2 × 3 × 5

140 = 2 × 2 × 5 × 7

Identify the prime factors that both numbers have in common and multiply them.

both have 2, 2 and 5, thus

HCF = 2 × 2 × 5 = 20

Multiply each factor the greatest number of times it occurs in either number.

2 : 3 times

3 : 1 time

5 : 2 times

7 : 1 time

LCM = 2 × 2 × 2 × 3 × 5 × 5 × 7 = 4200

HCF = 20

LCM = 840

Step-by-step explanation:

120 = 2×2×2×3×5

140 = 2×2×5×7

HCF: 2×2×5 = 20

LCM: 140×2×3 = 840

answer: it's upside down and i can't read it

step-by-step explanation:

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column