Can someone help it has to be a polynomial
The length of a rectangular sign is 6 inches more than half its width. The area of the sign is in (square inches). Write an equation in one variable for the area of this sign.

Width = 24 inches

Step-by-step explanation:

Let W represent the width of the rectangular sign.

The length of a rectangular sign is 6 inches more than half its width. It means that the length of the rectangular sign would be

W/2 + 6

The formula for determining the area of a rectangle is expressed as

Area = length × width

The area of the sign is 432 square inches. Therefore, the equation for the area of this sign would be

W(W/2 + 6) = 432

W²/2 + 6W = 432

Multiplying both sides of the equation by 2, it becomes

W² + 12W = 864

W² + 12W - 864 = 0

W² + 36W - 24W - 864 = 0

W(W + 36) - 24(W + 36) = 0

W - 24 = 0 or W + 36 = 0

W = 24 or W = - 36

Since W cannot be negative, then

W = 24

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