Flying to Kimpala with a tail wind a plane averaged 158km/hr. On the return trip the plane only average 112km/hr. While flying back into the same wind find the speed of the wind and the speed of the plane still in air?

The speed of wind and speed of plane in still air  are  23  and  135 km/h respectively.

Step-by-step explanation:

Let the speed of wind and speed of plane in still air  are  w  and  p km/h respectively.  

The effective speed on onward journey was  

 ................(1)

The effective speed on return journey was  

..............(2)

Adding equation (1) and equation (2) we get,  

⇒

⇒

⇒

Putting value of in we get:

⇒

⇒

⇒

Therefore ,The speed of wind and speed of plane in still air  are  23  and  135 km/h respectively.

i believe the correct answer is b.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.