On the coordinate grid of a map. Jeff's house is located at (9, 5). Hannah's house is at (-5, -5). Kenya's house is located at the midpoint between Jeff and Hannah's houses. What is the distance from Hannah's house to Kenya's house?

The distance from Hannah's house to Kenya's house is 8.6 units.

Step-by-step explanation:

It is given that,

Kenya's house is located at the midpoint between Jeff and Hannah's houses.

Kenya's house = Midpoint of (9,5) and (-5,-5)

The formula to find the midpoint is that :

Midpoint =

Here, (x1,y1) = (9,5) and (x2,y2) = (-5,-5)

Midpoint =

⇒

⇒

Therefore, the Kenya's house is located at (2,0).

To find the distance from Hannah's house to Kenya's house :

The distance between Hannah's house located at (-5, -5) and Kenya's house located at (2,0) must be found using the distance formula.

The distance formula is given by :

Distance =

Here, (x1,y1) = (-5,-5) and (x2,y2) = (2,0).

Distance =

⇒

⇒

⇒

⇒ 8.6 units.

Therefore, the distance from Hannah's house to Kenya's house is 8.6 units.

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step-by-step explanation:

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d