Please can someone help?

121

Step-by-step explanation:

First we find angles of triangle:

First angle is: 180-115=65

Secend angle is:360-304=56

Sum of all angles in triangle is 180. So the 3th angle of triangle is:

180-(65+56)=180-121=59

Sum of x and 3th angle is 180, then

X=180-59=121

Step-by-step explanation:

<ABC +<ABE = 180°(straight angle)

<ABC = 180-115° = 65°

<A = 360°-304° = 56° ( complete angle)

external angle of a triangle is equal to the sum of two opposite interior angles.

therefore, x = 56°+65°= 121°

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.