A manufacturer of bolts has a quality-control policy that requires it to destroy any bolts that are more than 2 standard deviations from the mean. The quality-control engineer knows that the bolts coming off the assembly line have mean length of 13 cm with a standard deviation of 0.10 cm. For what lengths will a bolt be destroyed?

bolts of length more than , and less than will be destroyed

= 13.20 cm and 12.80 cm

Step-by-step explanation:

Here we have , A manufacturer of bolts has a quality-control policy that requires it to destroy any bolts that are more than 2 standard deviations from the mean. The quality-control engineer knows that the bolts coming off the assembly line have mean length of 13 cm with a standard deviation of 0.10 cm. We need to find For what lengths will a bolt be destroyed .Let's find out:

A manufacturer of bolts has a quality control policy that requires it destroy any bolts that are more than 2 standard deviations from the mean.

mean length=

standard deviation=

2 standard deviation from mean=

Therefore, bolts of length more than , and less than will be destroyed

= 13.20 cm and 12.80 cm

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

the two may have that, even a breakdown is probably offered