Can anyone help me, please with these to question

it is due today, please no one would help me

First figure: An example of set C is {9 , 11 , 13}

Second figure:

Step-by-step explanation:

First figure:

Let us explain the meaning of subset

If set X subset set Y, that means every element in set X is in set Y and some elements in set Y are in set X

∵ U is the universal set ⇒ contains all elements in the problem

∵ U = {5 , 6 , 7 , 8 , 9 , 10 , 11 , 12 , 13 , 14 , 15}

∵ A = {5 , 6 , 7 , 8}

∵ B = {5 , 7 , 9 , 11 , 13 , 5}

- All the elements in set B are odd numbers

∵ C is subset of B

∴ All elements on C belongs to B

- That means the elements in C must be some elements of B

∴ C could be {9 , 11 , 13} OR {5 , 7 , 9 , 15} OR {7 , 9} OR .........

∴ An example of set C is {9 , 11 , 13}

Second figure:

Let us explain the meaning of complement

Complement of a set is all the elements in the universal set except the elements in this set

Let us list U and B from the figure

∵ U = {1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 , 11}

∵ B = {2 , 3 , 4 , 5 , 7}

- To find B' list all the elements in set U except the elements in set B

∴ B' = {1 , 6 , 8 , 9 , 10 , 11}

To find the probability of B', find n(B') the number of elements of set B' and n(U) the number of elements in set U, then find  

∵ Set B' has 6 elements

∵ n(B') = 6

∴ Set U has 11 elements

∴ n(U) = 11

∴

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°