Please help me with the question shown below
Question 2
a) and b)

a)59.30m

b)71.53m

Step-by-step explanation:

so from my poor diagram

SOHCAHTOA

IN A WE USE TAN

Tan 56=opposite/40

tan 56=1.4827*40

=59.30

in b the distance from the top of the cliff to the object is the hypotenuse

(59.30)

59.30²+40²=5116.49

√5116,49

=71.53 m

i hope it does help if you dont understand any point pliz ask

ou would have 12 of each