In an examination, Adenike obtained 19marks more than musa. if adenike had obtained one and half times her own mark, she would have score 6 marks more than twice musa mark. find the mark score by each of them.

Adenike scored 64 marks, while Musa scored 45 marks

Step-by-step explanation: We shall start by assigning letters to each unknown variable. Let Adenike’s mark be d while Musa’s mark shall be m.

First of all, if Adenike obtained 19 marks more than Musa, then if Musa scored m, Adenike would score 19 + m (or d = 19 + m). Also if Adenike has obtained one and half her own mark (which would be 1 1/2d or 3d/2), it would have been equal to 6 times more than twice Musa’s mark (or 6 + 2m). This can be expressed as

3d/2 = 6 + 2m. So we now have a pair of simultaneous equations;

d = 19 + m ———(1)

3d/2 = 6 + 2m ———(2)

Substitute for the value of d into equation (2), if d = 19 + m

(3{19 + m})/2 = 6 + 2m

By cross multiplication we now have

3(19 + m) = 2(6 + 2m)

57 + 3m = 12 + 4m

We collect like terms and we have

57 - 12 = 4m - 3m

45 = m

We now substitute for the value of m into equation (1)

d = 19 + m

d = 19 + 45

d = 64

So Adenike scored 64 marks while Musa scored 45 marks

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