In a study of the accuracy of fast food drive-through orders, Restaurant A had 242 accurate orders and 55 that were not accurate. a. Construct a 90% confidence interval estimate of the percentage of orders that are not accurate. b. Compare the results from part (a) to this 90% confidence interval for the percentage of orders that are not accurate at Restaurant B: 0.171less thanpless than0.245. What do you conclude?

(a) The 90% confidence interval estimate of the percentage of orders that are not accurate in Restaurant A is (0.148, 0.222).

(b)  Restaurant B has more proportion of not accurate orders.

Step-by-step explanation:

The (1 - α)% confidence interval for population proportion is:

(a)

In Restaurant A the number of not accurate orders was x = 55 of n = 297 orders.

The sample proportion of not accurate orders in Restaurant A is:

The critical value of z for 90% confidence level is:

Compute the 90% confidence interval estimate of the percentage of orders that are not accurate in Restaurant A as follows:

Thus, the 90% confidence interval estimate of the percentage of orders that are not accurate in Restaurant A is (0.148, 0.222).

(b)

The 90% confidence interval estimate of the percentage of orders that are not accurate in Restaurant B is (0.171, 0.245).

The confidence interval for Restaurant B indicates that between 17.1% to 24.5% orders are inaccurate.

The values of this interval is more than that for Restaurant A.

So, it can be concluded that Restaurant B has more proportion of not accurate orders.

hi how are you doing today, if you need just ask me.

step-by-step explanation: