Use the laws of Boolean algebra to show that the two Boolean expressions in each pair are equivalent. Show that a. xy + xy = x. b. Show that xy + zx = (x + y)(z + x) c. x + xy = x

a) b) and c) is proven :)

Step-by-step explanation:

a)

( For a) we used Boolean law like always true, and

a1=1a= a)

b)    

( For we used double negation , and De Morgans law and )

c) x+xy=x(1+y)=x1=x

(For c) we used Distribution law a(b+c)=ab+ac, and identity a1=1a=a)

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step-by-step explanation:

i think this could be a possible answer (1 / 84) -1

good luck! : d