A circle centered at (6,-8) has an x-intercept at (-7,0). Find the exact radius of the circle.

r^2 = 233

Step-by-step explanation:

We are provided with a center

and a x - intercept

Center - ( 6 , -8)

Point - ( -7 , 0)

The formula of a circle

( x - a) ^2 + ( y - b) ^2 = r^2

(x, y) - point

(a, b) - center

r^2 - radius

( a, b) = (6 , -8)

a - 6

b - -8

Insert the center into

( x - 6)^2 + ( y -(-8)^2 = r^2

( x - 6)^2 + ( y + 8)^2 = r^2

Insert the point

( x, y) = ( -7 , 0)

x - -7

y - 0

( x - 6)^2 + ( y + 8)^2 = r^2

( -7 - 6)^2 + ( 0 + 8)^2 = r^2

( -13)^2 + ( 8)^2 = r^2

169 + 64 = r^2

233 = r^2

The radius of the circle is

r^2 = 233

i believe its the last graph