Peter is giving marbles to some children at a carnival. He has 5 red marbles, 4 blue marbles, and 3 yellow marbles. If Peter selects a marble randomly without looking, what is the probability that he will give a blue marble to the first child and then a yellow marble to the second child?

1/11 = 0.09

Step-by-step explanation:

problem best done with a tree diagram. let's focus on the blue branch for child 1. the probability of child 1 getting a blue marble is 4/12. now since he's choosing randomly and we assuming that after giving it away, there is 12-1=11 marbles left, the second child will have the probability 3/11 of getting a yellow marble. multiple those probabilities

4/12 × 3/11

1/3 × 3/11

3/33

1/11

1. is 4 and 2. is 3

step-by-step explanation:

so if you look at the first one you see that 1 is to 4 and 2 is to 8 and so on, so you can see for every 1 there is a times 4 so if it were 3 then it would be 3*4 and it is 12

for number 2 it is 3 because 1 is to 3 and 2 is to 6 so for every 1 there is 3 so if it were 3 then there would be 3*3 = 9